in reply to Re: Re: Re: Test for standard input
in thread Test for standard input
Sorry, I cannot resist. Your code is ummmm doing lots of things that I do not think are what you intend.
The more idiomatic way of saying this is$ARGS = @ARGV; if ( -t and $ARGS eq 0 ) { }
I would also like to point out that you are testing the wrong kind of equality in your code -- you used the string equality test ( eq ) instead of the numeric test ( == ). In this case it worked, but it will someday drive you nuts trying to hunt this kind of bug down.die "No input found\n" if ( -t and @ARGV == 0 );
If I have figured this out correctly, you are trying to parse some command line options. I would strongly recommend using Getopt::Long, a core module that does this job very well.$names++, shift if $ARGV[0] eq "-l";
I am assuming you really mean to shift the argument you just parsed out of @ARGV. Unfortunately, shift with no arguments assumes you mean @_, which is not @ARGV. Again, it likely works in this case, but I really doubt this is your intended affect.
The same holds true for the next line.
This code will never be executed. I am assuming it is a hold-over from your previous problems. The 'if' at the top of the program makes certain that @ARGV has to have something in it.@ARGV = "-" unless @ARGV;
The assignment back to @ARGV is a little.... ugly IMHO. It took me several tries to figure out what it is doing. I would likely write this expression as
but this is likely more a stylistic thing.exit 0 unless ( grep { -T or $_ eq "-" } @ARGV );
Oh, good use of the -w flag. It appears, though, you forgot to use strict. It will seem a pain at first, but it will really help as your programs get longer and more complex.
Mik
mikfire
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Re: Re: Re: Re: Re: Test for standard input
by BUU (Prior) on Oct 03, 2002 at 23:57 UTC | |
by mikfire (Deacon) on Oct 04, 2002 at 04:07 UTC |
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