Re: Or Operator

[fruiture]

The magic term is "operator precedence", it determines the order of execution or your atomic expressions.

A = B or C;
# as "=" has higher precedence than "or" it binds it's 
# arguments "tighter", so this is equivalent to
(A = B) or C;
# so your expression is a disjunction
# which executes the left operand
(A = B)
# being an assignment, which returns B in the end
# and if that's false, the disjunction (or)
# returns C, which is irrelevant, because that's in void 
# context

# but you want
A = (B or C)
# because that's an assignment, an assignment
# evaluates the right operand first
(B or C)
# which itself is a disjunction again and works as described
# above, returning B if true, otherwise C
# and that is then assigned to A, which must be an lvalue

# that means in Perl
my $page = ( $cgi->param("page") or "login" );
# or by using the high-precedence-OR "||"
my $page = $cgi->param("page") || "login";
# because "||" has higher precedence than "="

see perlop

[rjahrman]

I have another similar line:
$ftp = Net::FTP->new("ftp.$dom", Debug => 0) or $loginerror = "Error message.";

Should this work like I think it does?

[ysth]

If you think it will set $ftp to the result of the new method call, and if that was false set $longin error, it will.