Re^4: Reverse engineering a formula...

in reply to Re^3: Reverse engineering a formula...
in thread Reverse engineering a formula...

Not every number necessarily needs to be part of the formula (obviously its 2 or more numbers in some combination of addition and/or subtraction). Those two numbers could simply not be part of the formula.

- Devnul

Comment on Re^4: Reverse engineering a formula...

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Re^5: Reverse engineering a formula... by Skeeve (Parson) on Jun 13, 2006 at 10:41 UTC
As I said before: Not enough information... It seems as if your formular is something like this (untested code of course): `my @sign=( .... ); # Some combination of -1, 0 1 my @sum= map { $sign[$i] * $VAR1[$i] } (0..$#VAR1); print eval join ' + ', @sum;` [download] Now you "only" need to get the correct combination of -1, 0 and 1 for @sign, which is a "simple" combinational task but will be very lengthy... `s$$([},&%#}/&/]+}%&{});#$&&s&&$^X.($'^"%]=\&(\|?{%` `+`.+=%;.#_}\&"^"-+%*).}%:##%}={~=~:.")&e&&s""`$''`"e	[reply] [d/l] [select]

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Re^5: Reverse engineering a formula...
by Skeeve (Parson) on Jun 13, 2006 at 10:41 UTC

my @sign=( .... ); # Some combination of -1, 0 1
my @sum= map { $sign[$i] * $VAR1[$i] } (0..$#VAR1);
print eval join ' + ', @sum;
[download]

s$$([},&%#}/&/]+}%&{})*;#$&&s&&$^X.($'^"%]=\&(|?*{%
+.+=%;.#_}\&"^"-+%*).}%:##%}={~=~:.")&e&&s""`$''`"e

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