in reply to Schwartzian Transform vs. Building Hash of Function Results, Then Sorting on Function Results
in thread Schwartzian Transform
davebaker,
In both cases, you are calculating the expensive_func() only once per item and sorting the list based off the result of the expensive_func(). The biggest difference is that in the standard ST, you do it in a single step and have no left over variable.
In both cases, you are calculating the expensive_func() only once per item and sorting the list based off the result of the expensive_func(). The biggest difference is that in the standard ST, you do it in a single step and have no left over variable.
Cheers - L~R
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Left over variable
by davebaker (Pilgrim) on Oct 16, 2006 at 19:35 UTC |
In Section
Cool Uses for Perl