Re^2: if ($2) behaves differently than if (defined $2)

[radiantmatrix]

That's a choice quote. Put another way, the OP is suffering from some confusion that if (defined $x) is intended to be the same as if ($x). In fact, they serve different purposes.

defined tests whether a variable has any value -- a false value is still a value.

Short demonstration code:

my $x;
demonstrate();

$x = 1;
demonstrate();

$x = 0;
demonstrate();

sub demonstrate {
  if (defined $x) { print "\$x has value $x\n"; }
  else { print "\$x is undefined\n"; }

  if ($x) { print "\$x evaluates as TRUE\n"; }
  else { print "\$x evaluates as FALSE\n"; }

  print "\n";
}

This produces the following output:

$x is undefined
$x evaluates as FALSE

$x has value 1
$x evaluates as TRUE

$x has value 0
$x evaluates as FALSE

[repellent]

Apparently, in Lisp, this is referred to as a semi-predicate problem.

The very fact that you are using


    if ($2)

followed by

    $price = $1 . "." . $2

shows that you are using $2 as a semi-predicate, i.e. to show validity and to hold value.

Next time, whenever you use if ($var), you should consider if $var needs to be a full-predicate, i.e. strictly a boolean to only show true-or-false.