Re^3: "2" | "8" = ":" and 2|8=10

in reply to Re^2: "2" | "8" = ":" and 2|8=10
in thread "2" | "8" = ":" and 2|8=10

Bitwise operators are the only place where there's a difference between strings and numbers.
No. It matters for post-increment as well.

I think you're wrong there. Postincrement only works different for strings if they start with a letter. For strings like "199" it makes no difference: you just get 200. And other strings apparently are converted to a number first, as $x = "2A"; $x++ produces 3.

It's a deliberate decision, and well worth the offset. It allows you to use bitfields that aren't restricted to 32 (or 64) bits.

Yes, I don't question the functionality, that is useful. But the typical Perl thing to do would have been to provide different operators for strings and for numbers. Just as with = vs eq and + vs ..

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Re^4: "2" \| "8" = ":" and 2\|8=10 by JavaFan (Canon) on Nov 04, 2011 at 12:59 UTC
I think you're wrong there. Postincrement only works different for strings if they start with a letter. For strings like "199" it makes no difference: you just get 200. And other strings apparently are converted to a number first, as $x = "2A"; $x++ produces 3. `$ perl -E '$x = $y = "A3"; $y + 0; $x++; $y++; say "$x $y"' A4 1 $` [download] The difference is, $y has an integer (as well as a string value), where $x doesn't. And hence, the post-increment value differs.	[reply] [d/l]

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Re^4: "2" | "8" = ":" and 2|8=10
by JavaFan (Canon) on Nov 04, 2011 at 12:59 UTC

I think you're wrong there. Postincrement only works different for strings if they start with a letter. For strings like "199" it makes no difference: you just get 200. And other strings apparently are converted to a number first, as $x = "2A"; $x++ produces 3.

$ perl -E '$x = $y = "A3"; $y + 0; $x++; $y++; say "$x $y"'
A4 1
$
[download]

[reply]
[d/l]

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