in reply to Re: Foo is not a Bar, why?
in thread Foo is not a Bar, why?
Or using the nicer-looking use base. It will complain that the Bar package is empty, so I put a sub in it, but then it works fine.
my $foo = Foo->new; print "foo is".($foo->isa( 'Bar' ) ? '' : ' _not_')." a Bar\n"; package Bar; sub null {} package Foo; use base Bar; sub new { bless {},shift }
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Re: Re: Re: Foo is not a Bar, why?
by liz (Monsignor) on Dec 18, 2003 at 15:49 UTC | |
by PodMaster (Abbot) on Dec 18, 2003 at 15:53 UTC | |
by bart (Canon) on Dec 18, 2003 at 22:46 UTC | |
by Mr_Person (Hermit) on Dec 18, 2003 at 16:00 UTC |
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