Re: Integer overflow in Perl and C

[rob_au]

3. Are there any other (neater) implementations of my script above

In terms of the original problem as presented, I believe that it an alternate approach employing the exponentiation operator/functions would be more efficient and side-step the format conversion problems.

In Perl:

perl -le 'print $_, ": 0 to ", 2**$_ - 1 for 0..32'

In C:

#include <stdio.h>
#include <math.h>

int main (void) {

    int i;
    for (i = 0; i <= 32; i++) 
        printf("%d: 0 to %.f\n", i, pow(2, i) - 1);

    return(0);
}

Both implementations are capable of outputting ranges of unsigned integer numbers for up to 64 bits (untested beyond).