in reply to shift vs @_
My favourite reason to use shift, that's not necessarily right, but right for me? I can't easily do my $x, $y = @_;
It's valid perl. It assigns a scalar. You will likely run into the bug right away, but who knows when, eh?
I can't do the equiv w/ shift in the form of...
Unless i do..my $x = shift; my $y = shift;
Now I have to worry about indicies. At least shift requires none.my $x = $_[0]; my $y = $_[1];
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Re^2: shift vs @_
by radiantmatrix (Parson) on Oct 06, 2006 at 14:33 UTC | |
by exussum0 (Vicar) on Oct 06, 2006 at 14:39 UTC | |
by radiantmatrix (Parson) on Oct 06, 2006 at 16:36 UTC | |
by exussum0 (Vicar) on Oct 06, 2006 at 20:01 UTC | |
Re^2: shift vs @_
by Cop (Initiate) on Dec 23, 2007 at 19:48 UTC | |
by blazar (Canon) on Dec 25, 2007 at 15:24 UTC |
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