http://www.perlmonks.org?node_id=816636


in reply to perl subtraction

You've just run into a problem that computer programmers have dealt with for decades: floating point numbers do not form a closed set under the operations of normal arithmetic. The reason is, of course, that floating point numbers only represent a finite subset of rational numbers.


Information about American English usage here and here. Floating point issues? Please read this before posting. — emc