Perl sha256 question

[Anonymous Monk]

Hi,

The output I am getting from SHA256 is different from what I get from other online tools:

use Digest::SHA qw(sha256_hex);

print sha256_hex(5472151337331275);
# 32838cef9e4571b4fa9a5297e265cf860a31774de3ca339878d87238af604a45

#result from other online tools:
# b5951ee4a7cbfdc9df6b1b74de2d1ba865de40796c756cebe88a806c5a7b9e60

Am I missing something?　Could someone enlighten me?

Thanks in advance :)

[Athanasius]

Tip #2 from the Basic debugging checklist: Display the contents of variables using print or warn:

use strict;
use warnings;
use Digest::SHA qw( sha256_hex );

my $h = 5472151337331275;
print "\$h = >$h<\n\n";
print sha256_hex($h), "\n";

On Perl v5.24.0, which is 64-bit:

17:40 >perl 1639_SoPW.pl
$h = >5472151337331275<

b5951ee4a7cbfdc9df6b1b74de2d1ba865de40796c756cebe88a806c5a7b9e60

17:40 >

— which is as expected. But on Perl v5.14.4, which is 32-bit:

17:33 >perl 1639_SoPW.pl
$h = >5.47215133733128e+015<

32838cef9e4571b4fa9a5297e265cf860a31774de3ca339878d87238af604a45

17:34 >

As Anonymous Monk says, the fix is to turn the argument from a number into a string.

Hope that helps,

[Anonymous Monk]

Thank you so much :)

On the same machine and Perl version, when I set the number to a variable, it works:

use Digest::SHA qw(sha256_hex);

my $num = 5472151337331275;
print sha256_hex($num);
# b5951ee4a7cbfdc9df6b1b74de2d1ba865de40796c756cebe88a806c5a7b9e60

What difference does setting it to a variable make?

[Athanasius]

It looks as though the assignment is performing a stringification. I haven’t been able to replicate this behaviour. What is your platform, and what is the output of perl -V?

[Anonymous Monk]

print sha256_hex('5472151337331275');

[Anonymous Monk]

That works! Great thanks :))