Arrow Operator Oddment

[MeowChow]

Wherefore does the following code work?

@l = 0..10; %h = (a => 1, b => 2); print @l->[4]; # prints 4 print %h->{b}; # prints 2

My reading of perlop has me convinced that this is an unintended syntactic feature.

   MeowChow                                   
               s aamecha.s a..a\u$&owag.print

[Abigail-II]

My reading of perlop has me convinced that this is an unintended syntactic feature.

And that's exactly what it is. When using the arrow, Perl will see whatever is left of it as a reference. Including if you have something like @l or %h.

Note that you will get the warning
Using an array as a reference is deprecated
in Perl 5.8.0.

Abigail

[MeowChow]

Deprecated, eh? Somehow I don't get the impression that it was ever precated to begin with... :-)

   MeowChow                                   
               s aamecha.s a..a\u$&owag.print

[Cody Pendant]

Can you explain that a bit for those less enlightened monks?

I'm a bit baffled. I don't see what the problem is.
--


($_='jjjuuusssttt annootthheer
     pppeeerrrlll haaaccckkeer')=~y/a-z//s;print;