Re: $[ is under respected.

[Anonymous Monk]

Does anyone understand this:

my @foo = qw /foo bar baz quux/;
$[ = 2;
print $foo[2], "\n";
print $foo[1], "\n";
print $foo[0], "\n";
__END__
foo
quux
foo

If $[ is set to 2, $foo[2] is the first element (foo). It seems that $foo[1] is the last element (quux), which is logical because 1 == $[ - 1. But while 0 == $[ - 2, $foo[0] isn't equal to penultimate element (baz), but it's equal to the first element (foo) - as if $[ doesn't effect an index equal to 0.