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### e

by tachyon (Chancellor)
 on Jul 16, 2004 at 08:19 UTC Need Help??

sub e { \$N=pop;\$a[\$_]=int(1+1/\$_)for 1..\$N;for(;\$N>9;print int\$x) {for(\$n=\$N--;--\$n;\$a[\$n]=\$x%\$n,\$x=10*\$a[\$n-1]+\$x/\$n){}} } e(1000);

NB: Based on work by Xavier Gourdon e

cheers

tachyon

Replies are listed 'Best First'.
Re: e
by Discipulus (Monsignor) on Jul 16, 2004 at 10:37 UTC
good morning wise one

A part obfu that for me is very obfuscated what you are printing out ?? a suit of numbers gorwing up of a char as the argoument is > 10.
the sequence have every time the same beginning without evident internal repetitions until the argoument is < 10000 ... which kind of number is ??
which kind of number is ??

It's e

He who asks will be a fool for five minutes, but he who doesn't ask will remain a fool for life.

EEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE!!!
perl -e 'print exp 1'
• perldoc -f exp
• perldoc -f log
NOW I KNOW WHY I 'M GRADUATED IN MEDIAVAL HISTORY !!

cheers lorenzo*
Re: e
by I0 (Priest) on Jul 17, 2004 at 06:04 UTC
sub e{ use integer; my @e=(1) x shift; for(1..@e*log(@e)/3){ for(reverse(1..\$#e)){ \$e[\$_-1]+=\$e[\$_]/\$_; \$e[\$_]%=\$_; } printf"%01d",\$e[0]; \$e[0]=0; \$_*=10 for @e; } }

Cool. Lovely piece of code.

Map gets it down to 105 chars - yes void maps are good for golf only!

sub e{ #234567890123456789012345678901234567890123456789012 @e=(1)x pop;map{map{\$e[\$_-1]+=\$e[\$_]/\$_;\$e[\$_]=10*(\$ e[\$_]%\$_)}reverse 1..\$#e;print int\$e[0];\$e[0]=0}1..@e } # or if you prefer whitespace and no void maps sub e{ @e=(1)x pop; for(1..@e){ for(reverse(1..\$#e)){ \$e[\$_-1]+=\$e[\$_]/\$_; \$e[\$_]=10*(\$e[\$_]%\$_) } print int \$e[0]; \$e[0]=0 } }

cheers

tachyon

Re^3: e
by mtve (Deacon) on Jul 17, 2004 at 09:36 UTC

Simple optimizations down to 86:

sub e{ #234567890123456789012345678901234567890123456789012 map{\$e[\$q-1]+=\$e[\$q]/\$q,(\$e[\$q]%=\$q--).=0for 1..(\$q=@e);\$e[0]=!print"@e"|0}@e=(1)x pop } e(1000);

Update from tybalt89 - 80 chars:

\$=[!print\$=]=!map{\$==\$=[\$#z]+=\$=[@z]/@z,(\$=[@z]%=1+\$#z--).=0}@z=@=for@ +==(1)x pop
Re^4: e
by shmem (Chancellor) on Sep 13, 2015 at 09:47 UTC
Re: e
by Anonymous Monk on Jul 18, 2004 at 02:43 UTC
You're missing a period :)
Re^2: e
by I0 (Priest) on Jul 18, 2004 at 08:21 UTC
sub e{ my @e=(1)x shift; my \$f="%d."; local \$|=1; for(1..@e*log(@e)/11){ for(reverse(1..\$#e)){ \$e[\$_-1]+=\$e[\$_]/\$_; \$e[\$_]=10000*(\$e[\$_]%\$_) } printf\$f,\$e[0]; \$e[0]=0; \$f="%04d"; } }

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