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Re^3: @array elements multiplication with another array elements.

by tobyink (Abbot)
on Oct 31, 2012 at 07:51 UTC ( #1001621=note: print w/replies, xml ) Need Help??

in reply to Re^2: @array elements multiplication with another array elements.
in thread @array elements multiplication with another array elements.

It uses a prototype of &\@\@. That means the two arrays get implicitly turned into arrayrefs by the Perl parser. The body of the sub just sees a coderef and two arrayrefs - not a flattened list. See perlsub.

perl -E'sub Monkey::do{say$_,for@_,do{($monkey=[caller(0)]->[3])=~s{::}{ }and$monkey}}"Monkey say"->Monkey::do'

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Re^4: @array elements multiplication with another array elements.
by grizzley (Chaplain) on Oct 31, 2012 at 08:31 UTC
    That's true! Wow, thanks, first example of prototypes being useful
    c:\>perl -le "sub f(\@\@) { print 'array ', ++$cnt ,': ', join ' ', @$ +_ for @_ } @a=(1..5, 11,12);@b=(13..15); f @a, @b" array 1: 1 2 3 4 5 11 12 array 2: 13 14 15

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[erix]: choroba: pretty impressive! :)
LanX imagines which nations would be dominating if the winter olympics were invented in East Asia
[LanX]: Corion: and that's the clue how Germany can dominate Handball tournaments, just continuing the domestic league and forbidding the best players of the world to attend :)
LanX (which would be a good scheme for England and football too)
[LanX]: If "Canada will play the Czech Republic for bronze on Saturday", that means Germany will play Syria in disguise...

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