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Re^3: @array elements multiplication with another array elements.

by tobyink (Canon)
on Oct 31, 2012 at 07:51 UTC ( [id://1001621]=note: print w/replies, xml ) Need Help??


in reply to Re^2: @array elements multiplication with another array elements.
in thread @array elements multiplication with another array elements.

It uses a prototype of &\@\@. That means the two arrays get implicitly turned into arrayrefs by the Perl parser. The body of the sub just sees a coderef and two arrayrefs - not a flattened list. See perlsub.

perl -E'sub Monkey::do{say$_,for@_,do{($monkey=[caller(0)]->[3])=~s{::}{ }and$monkey}}"Monkey say"->Monkey::do'

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Re^4: @array elements multiplication with another array elements.
by grizzley (Chaplain) on Oct 31, 2012 at 08:31 UTC
    That's true! Wow, thanks, first example of prototypes being useful
    c:\>perl -le "sub f(\@\@) { print 'array ', ++$cnt ,': ', join ' ', @$ +_ for @_ } @a=(1..5, 11,12);@b=(13..15); f @a, @b" array 1: 1 2 3 4 5 11 12 array 2: 13 14 15

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