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Re^2: $1 not "freezing" in an addition

by ikegami (Pope)
on Dec 16, 2012 at 14:13 UTC ( #1009066=note: print w/ replies, xml ) Need Help??

in reply to Re: $1 not "freezing" in an addition
in thread $1 not "freezing" in an addition

Perl does not guarantee what order the two operands of a binary operator will be evaluated in.

Operand evaluation order is documented and thus guaranteed for about half the ops*. And while it's not guaranteed for the other ops, it never changes (left-to-right for all ops (including **) except assignment ops).

* — Going from memory, operand evaluation order is documented for:

  • && || // and or xor ?:
  • = **= += *= &= <<= &&= -= /= |= >>= ||= .= %= ^= //= x=
  • , => (in scalar context)
  • .. ... (in scalar context)

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