in reply to Re^4: $1 not "freezing" in an addition
in thread $1 not "freezing" in an addition
$bar = "$1" + foo(); instead of $bar = $1 + foo();
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In Section
Seekers of Perl Wisdom
in reply to Re^4: $1 not "freezing" in an addition
in thread $1 not "freezing" in an addition
$bar = "$1" + foo(); instead of $bar = $1 + foo();
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