|Perl: the Markov chain saw|
d-mmm-yyyy to DOY (day of year)by Anonymous Monk
|on May 13, 2013 at 21:08 UTC||Need Help??|
Anonymous Monk has asked for the
wisdom of the Perl Monks concerning the following question:
Hi, hopefully someone might be able to help as I've been searching all night for a solution to this, and am running out of time.
I have to convert this date field (or add another field) to the day of year (DOY). It is currently in d-mmm-yyyy.
By Day of year, I mean 1st January 2013 would be 1. 2nd January would be 2.
Here is a snippet of my very large (7,000,000 row table)
many, many thanks