http://www.perlmonks.org?node_id=1052141


in reply to how to use perl variable in system command to run on unix

q prevents variable interpolation. So, $grep_date is not taking on the value 'Sep 02' inside your system call. It remains the literal string $grep_date. Try something like: 
my $cmd = 
    'cd /waslogs1/vfoneLog/cposapp && ls -lrt | grep -i "'
    . $grep_date
    . q(" | awk '{ print $9 }' > /home/cpos/CRM_Reports/output/filelis
+t.txt);
system $cmd;

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Also, system returns an exit status, not a command output. Look at qx.

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Re^2: how to use perl variable in system command to run on unix
by tousifp (Novice) on Sep 03, 2013 at 17:25 UTC

    I exceuted your lines like this but no result

     my $cmd = 'cd /waslogs1/vfoneLog/cposapp && ls -lrt | grep -i "'. $gr
+ep_date. q(" | awk '{ print $9 }' > /home/cpos/CRM_Reports/output/fil
+elist.txt);
system $cmd;

    [download]

    filelist.txt is not written

[reply]
[d/l]

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