Re: Re: Unix Perl and Html

[meccaxlr]

Thanks for your help thatguy monk! for security reasons my boss told me not to run a cron job for sudo printstatus. He told me to have my program read form 3 dump files in usr/lsys/printstatus which is the output of printstatus. He said running a sudo would be a bad idea. from there all i have to do is parse the files, any suggestions? Thanks a billion !

[thatguy]

do you have some examples of the output of printstatus? (you can change the names/ips to protect your network, we just want the formatting).

If the output is a single line per printer you can use my previous example, otherwise there might be some work involved :)

Update:if the output is something along the lines of


name display toner level 
----------------------------------- 
printer1 toner low 25% 
printer2 toner low 1%
printer3 etc etc etc


then this should work ok..

#!/usr/bin/perl -w
use strict;
use CGI;

my $main=new CGI;
print $main->header;
print $main->start_html("Printer Status");

open(STATUSFILE," your_outfile") || die "Cannot open logfile!: $!\n";
while(<STATUSFILE>) {
        chomp;
        if (! ($_=~ /-----------------------------------/)) {
                #my ($printer,$display,$toner,$level) = split(/ /, $_)
+;
                my @status = split(/ /, $_);
                if (($status[0] eq "name") && ($status[1] eq "display"
+)) {
                        print "<center><table width=250 border=1><tr a
+lign=center>\n";
                        for (@status) {
                                print "<td><b>$_</b></td>\n";
                        }
                        print "</tr>\n";
                } else {
                        for (@status) {
                                print "<td>$_</td>\n";       
                        }
                        print "</tr>\n";
                }
        }
}
print "</table>\n";       
close(STATUSFILE);
exit;


-p

[meccaxlr]

I just went into the files my boss specified. When i go into the directory /usr/lsys/printstatus under admin i come up with 3 files 'printstatus.out' 'lpc_status.printing1' and 'lpc_status.printing2'. when i go into printstatus.out there is this nice information window thats something like
name display toner level
-----------------------------------
printer1 toner low 25%

[meccaxlr]

I just went into the files my boss specified. When i go into the directory /usr/lsys/printstatus under admin i come up with 3 files 'printstatus.out' 'lpc_status.printing1' and 'lpc_status.printing2'. when i go into printstatus.out there is this nice information window thats something like
name display toner level
-----------------------------------
printer1 toner low 25%

[meccaxlr]

Thank you thatguy monk. Since I am new to perl does this program read from the printstatus file, parse it and send it to a log file??!?!

I'm just a perl peon

[thatguy]

Yes that should be the name of the printstatus file.

when i work on SOPW questions i use the monk's name as the name of the files involved.. I forgot to change that to something else..
-p

[meccaxlr]

#!/usr/bin/perl -w
use strict;
use CGI;

my $main=new CGI;
print $main->header;
print $main->start_html ("Printer Status");

open(usr/lsys/printstatus/printstatus.out ,"logfile.html");

while(<usr/lsys/printstatus/printstatus.out>) {
    chomp;
    if (! ($_=~/----------------------------/)) {
            #my ($printer,$display,$toner,$level) = split(/ /, $_);
        my @status = split(/ /, $_);
        if (($status[0] eq "name") && ($status[1] eq "display")) {

            print "<center><table width=250 border=1><tr align=center>
+\n";
            for (@status) {
                print "<td><b>$_</b></td>\n";
            }
            print "</tr>\n";
        }
    }
}
print "</table>\n";
close (usr/lsys/printstatus/printstatus.out);
exit;

Would this be an accurate representation of this program? Did i substitute the correct variables?

[thatguy]

that's close. The filehandle is a reference to the file, so instead of having the path to the file, it needs to be a keyword or decriptive word. Then inside the quotes you need to put the filename (with path).

Here's what it should look like:

#!/usr/bin/perl -w
use strict;
use CGI;

  # start new cgi process
my $main=new CGI;
  # print html headers
print $main->header;
  # print html tags and add title
print $main->start_html ("Printer Status");

  # open /usr/lsys/printstatus/printstatus.out under filehandle LOGFIL
+E
open(LOGFILE," /usr/lsys/printstatus/printstatus.out");
  # while there is data in LOGFILE
while(<LOGFILE>) {
    # remove newlines (\n) from input
    chomp;
    # if the imput is not the divider line
    if (! ($_=~/----------------------------/)) {
        # put the contents of the current line into the array @status
        # we are spliting on the space so that every word seperated by
        # a space becomes a new element in the array
        my @status = split(/ /, $_);
        # if the first element of @status does not equal 'name' (the t
+itle header
        if (($status[0] eq "name") && ($status[1] eq "display")) {
          # print the start of the table
            print "<center><table width=250 border=1><tr align=center>
+\n";
          # for each element in @status
            for (@status) {
            # print a new table cell
                print "<td><b>$_</b></td>\n";
            }
          # close the table row
            print "</tr>\n";
        }
    }
}
  # close the table
print "</table>\n";
  # close LOGFILE
close (LOGFILE);
exit;

if you are curious about some of the commands/functions that are used, type perlfunc:NameOfFunction in the super search.
-p