Re: regex remove blank/whitespace until first occurrence of specific character "["

Data::Dumper can't produce the output you desire. Behold:

Bareword found where operator expected at -e line 3, near "] String0"
        (Missing operator before String0?)
Bareword found where operator expected at -e line 4, near "] String1"
        (Missing operator before String1?)
Bareword found where operator expected at -e line 5, near "] String2"
        (Missing operator before String2?)
Bareword found where operator expected at -e line 6, near "] String3"
        (Missing operator before String3?)
Bareword found where operator expected at -e line 7, near "] String4"
        (Missing operator before String4?)
Bareword found where operator expected at -e line 8, near "] String5"
        (Missing operator before String5?)
Bareword found where operator expected at -e line 9, near "] String6"
        (Missing operator before String6?)
Bareword found where operator expected at -e line 10, near "] String7"
        (Missing operator before String7?)
syntax error at -e line 3, near "] String0"
Execution of -e aborted due to compilation errors.
[download]

To get all the matches from the m// operator, you need list context (which you already have), but also the /g option:

my @matches = $initialStr =~ /\d+:\d+:\d+/g;
[download]

Or, to get closer to your desired output:

my @matches = $initialStr =~ /\[ .*? \] \s* ( \[ .*? \] .* )/gx;
[download]

لսႽ† ᥲᥒ⚪⟊Ⴙᘓᖇ Ꮅᘓᖇ⎱ Ⴙᥲ𝇋ƙᘓᖇ

Comment on Re: regex remove blank/whitespace until first occurrence of specific character "[" Select or Download Code

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Re^2: regex remove blank/whitespace until first occurrence of specific character "[" by thanos1983 (Parson) on Mar 03, 2015 at 09:10 UTC
Hello choroba, Thank you for your time and effort answering my question. You are absolutely right it works perfect. I have so many things to learn. :D Seeking for Perl wisdom...on the process of learning...not there...yet!	[reply] [d/l] [select]


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