Re: perl behavior with print command

[NetWallah]

($note +=1) is an "lvalue" - i.e. a value that can be assigned to.

"0" (a constant) cannot be assigned to (It cannot take a different value), so perl complains.

Note "%=" is essentially an assignment operator.

[raghuprasad241]

Thank you NetWallah. That explains the problem.

[Discipulus]

next error will be print interpreted as a function.. because you have print (..) you can use the strange syntax print +(..) or the ugly print "",(..) one

L*