Contributed by Zombie dima
on Mar 27, 2002 at 00:20 UTC
Q&A
> CGI programming
Description: <input type="checkbox" name="checkbox" value="on" checked>
When I print the value of checkbox it prints blank instead of on, and thats why pearl code below always goes into else statement. What should I do so that I can check if the checkbox is marked or not?????? Thanks a lot!!!!
if ($field{'checkbox'})
{
# checkbox was checked
$chkbutton1 = "Yes send me news letter";
}
else
{
# checkbox left unchecked
$chkbutton1 = "No don't send me news letter";
}
Answer: How do I check if checkbox in the form was checked or not?
contributed by Flame First, allways "use CGI;" to get values, it's simple, safe, and effective.
Second, you need to make sure you specify a value for the checkbox if you really want to be able to see if it is checked.
Eg: <INPUT TYPE=CHECKBOX NAME="MyBOX" VALUE="on">
Code:
if($cgi->param('MyBOX') eq 'on'){
#Do whatever
}else{
#...
}
This should also work:
if($cgi->param('MyBOX')){
#Do whatever
}else{
#...
}
But the first is a little more paranoid.
Hope this helps... |
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