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how do i replace brackets in a regex?

by Superman (Acolyte)
on Apr 09, 2002 at 18:00 UTC ( #157804=categorized question: print w/replies, xml ) Need Help??
Contributed by Superman on Apr 09, 2002 at 18:00 UTC
Q&A  > regular expressions


Description:

i have a scalar as follows
$journal = STRUCTURE (LONDON)
when i query this in cgi, it is done so as
STRUCTURE+(LONDON)
this gives the + in the middle to complete the URL.
However in order to query the URL PROPERLY i need for my string to read
$journal = STRUCTURE LONDON
so that the CGI query is STRUCTURE+LONDON.
how can i write a regex that will remove these brackets from the string???
$journal = ~ s/ (help remove brackets) //g;
thanks in advance

Answer: how do i replace brackets in a regex?
contributed by particle

$journal =~ tr/)(//d;

Answer: how do i replace brackets in a regex?
contributed by Schuk

or

$journal =~ s/(\)|\()//g;

"s" for replace
"\)" and "\(" for escaping the brackets
"|" for or
and the whole thing in "(..)" because you want to replace it with nothing "//"
"g" finally stands for global -> replacement doesnt stop when you hit the first bracket.

Answer: how do i replace brackets in a regex?
contributed by I0

or $journal =~ s/[()]//g;

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