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lt versus le in string comparision

by Len (Friar)
on Jun 13, 2002 at 13:47 UTC ( #174190=categorized question: print w/replies, xml ) Need Help??
Contributed by Len on Jun 13, 2002 at 13:47 UTC
Q&A  > strings


Can anyone explain me this:
$char = 'a'; while ($char lt 'z') { print $char; $char++; }
prints as expected the characters (a..y) but if I change lt in le in the while expression:
while ( $char le 'z' )
it prints (a..yz) instead of the expected (a..z)

Answer: lt versus le in string comparision
contributed by Abigail-II

Consider this:

my $str = 'y'; $str ++; print "$str\n"; $str ++; print "$str\n";
This will print
Now, both z and aa are less or equal to z. It isn't until you reach za that you have a string that isn't less or equal to z.


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