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(zdog) Re: Sequential Replacement

by zdog (Priest)
on Jul 09, 2002 at 17:53 UTC ( #180555=note: print w/replies, xml ) Need Help??


in reply to Sequential Replacement

Here's a little different way of doing it that may give you some other ideas:

use strict; use warnings; my @array = qw (zero one two); my $str = "blah ##REP0## blah ##REP1##\nblah ##REP2##\n"; $str =~ s/##REP(\d+?)##/$array[$1]/g; print $str;

Update: Another idea is to replace the ##*##'s with %s and do:

$str = sprintf ($str, @array);

Just a thought ...

Zenon Zabinski | zdog | zdog@perlmonk.org

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[jedikaiti]: RonW++ #I have so much accumulated in my memory that finding the right item at a given moment often fails
[LanX]: corion only > 800 lines
[stevieb]: ahhh you're talking about the actual Makefile, not the PP Makefile.PL
[Corion]: LanX: But most of that is just setup of variables to be used later, like CC , LIB etc.
[LanX]: yes and some builders try to avoid it
[RonW]: :)

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