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Perl: the Markov chain saw

RE: RE: I've had this much school:

by garyt (Initiate)
on Feb 03, 2000 at 02:20 UTC ( #2759=note: print w/replies, xml ) Need Help??

in reply to RE: I've had this much school:
in thread I've had this much school:

It's a train of camels.

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RE: RE: RE: I've had this much school:
by error27 (Novice) on Feb 03, 2000 at 12:28 UTC
    "The camel has a single hump; The dromedary, two; Or else the other way around. I'm never sure. Are you?" ~ Ogden Nash.

      I love old Ogden, but on this
      I must be quite contrary.
      This memory trick distinguishes
      Bactrian from dromedary.

      First, capitalize each one's name.
      Now take the initial letter
      And turn it ninety degrees to left
      To make the shapes match better.

      Observe the camels' backs and lo!
      The answer's plain to see.
      Two humps are on the letter B
      But one hump on the D.

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[ovedpo15]: another question about regex. if I have a string like this: "a/b/,c/d/e,5" I would like to remove the string after the last comma so the output will be "a/b/,c/d/e" how to do so?
[Corion]: ovedpo15: You could split on comma, and then join everything together, except the last part. Or you could match and make sure that the last part has no comma, like qr!,[^,]+$!, or you could use rindex.
[ovedpo15]: But I don't know the length of the string. will it still work?
[ovedpo15]: The only thing I know is that there is a comma at the end and a value after that
[hippo]: Try it and see. Your computer won't explode.
[Corion]: length will tell you the length of a string.

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