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it's easy: 326
An approximation to the Camel Problem Ceiling((3-sqrt(3))*4^(n-3)) + 1 Ok, i've cheated: http://public.research.att.com/~njas/sequences/?q=2%2C2%2C2%2C3%2C7%2C22%2C83&sort=0&fmt=0&language=english&go=Search In reply to Re: 2, 2, 2, 3, 7, 22, 83, ...
by gnujsa
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