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How do I put bracket on substring(s) of a string?

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Contributed by monkfan on Aug 27, 2005 at 03:19 UTC
Q&A  > strings


I am trying to put the bracket in a string given the set of its substrings. Like this:

Answer: How do I put bracket on substring(s) of a string?
contributed by monkfan

This is an attempt to save a thread in SoPW which I thought can be useful for others.

There are already incredible answers in the thread, so feel free to check in SoPW. Please don't misunderstand me. I honestly think this can be useful. I don't mean to boost my XP here, or in that thread which I posted.

One possible answers is given by good sgifford

#!/usr/bin/perl -w use strict; my $s1 ='CCCATCTGTCCTTATTTGCTG'; my @a1 = qw(ATCTG ATTTG); my $s2 ='ACCCATCTGTCCTTGGCCAT'; my @a2 = qw(CCATC); my $s3 ='CCACCAGCACCTGTC'; my @a3 = qw(CCACC CCAGC GCACC); my $s4 ='CCCAACACCTGCTGCCT'; my @a4 = qw(CCAAC ACACC); put_bracket($s1,\@a1); put_bracket($s2,\@a2); put_bracket($s3,\@a3); put_bracket($s4,\@a4); sub put_bracket { my( $str, $ar ) = @_; foreach my $subs ( @$ar ) { # Construct a regexp with [\[\]] between all the letters my $newsub = join '[\[\]]?', split //, $subs; $str =~ s/($newsub)/[$1]/g; } # Now de-nest the brackets in the string my $depth = 0; my $newstr = ''; foreach my $c ( split //, $str ) { if ( $c eq '[' ) { $newstr .= $c if $depth++ == 0; } elsif ( $c eq ']' ) { $newstr .= $c if --$depth == 0; } else { $newstr .= $c; } } return $newstr; }
More can be found here. Don't vote my root posting but vote those remarkable answers you will find there.
Answer: How do I put bracket on substring(s) of a string?
contributed by Roy Johnson

#!perl use strict; use warnings; my @testdata = (['CCCATCTGTCCTTATTTGCTG', [qw(ATCTG ATTTG)]] ,['ACCCATCTGTCCTTGGCCAT', [qw(CCATC)]] ,['CCACCAGCACCTGTC', [qw(CCACC CCAGC GCACC)]] ,['CCCAACACCTGCTGCCT', [qw(CCAAC ACACC)]]); for (@testdata) { my ($str, $pats) = @$_; print put_bracket($str, @$pats), "\n"; } sub put_bracket { my $str = shift; # Combine multiple match strings into alternations my $rx = join '|', @_; my @brackets; # Store bracket points for every match while ($str =~ /(?=($rx))/g) { push(@brackets, [$-[0], length($1)+$-[0]]); } # Condense overlapping brackets for my $i (0..$#brackets-1) { if ($brackets[$i][1] >= $brackets[$i+1][0]) { $brackets[$i+1][0] = $brackets[$i][0]; @{$brackets[$i]} = (); } } # Apply the brackets (from back to front) while (@brackets) { my $b = pop @brackets; next unless @$b; substr($str, $b->[1], 0) = ']'; substr($str, $b->[0], 0) = '['; } return $str; }
Answer: How do I put bracket on substring(s) of a string?
contributed by jdporter

sub put_brackets { my( $str, @pats ) = @_; my $mask = ' ' x length $str; my $ofs = 0; for ( @pats ) { $ofs = index $str, $_, $ofs; last if $ofs < 0; # this pattern not found; look for no more. substr $mask, $ofs, length($_), 'a' x length($_); } # print "string= '$str'\n"; # print "mask = '$mask'\n"; join '', map sprintf( /a/ ? '[%s]' : '%s', substr $str, 0, length($_), '' ), split /\b/, $mask }

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