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Re: changing the position of an element in an array

by blazar (Canon)
on Nov 17, 2005 at 13:29 UTC ( #509399=note: print w/replies, xml ) Need Help??


in reply to changing the position of an element in an array

my $pos; for (0..$#array) { $pos=$_ and last if $array[$_] eq $wanted; } @array[$pos,-1]=@array[-1,$pos];

And what if no one of them matched? (Left as an exercise to the reader)

Update: it was a wonderfully neat solution (which is the reason why I posted it!) to another problem!!

Not just as neat:

my $pos; for (0..$#array) { $pos=$_ and last if $array[$_] eq $wanted; } @array=@array[0..$pos-1, $pos+1..$#array, $pos];

And what if no one of them matched? (Left as an exercise to the reader ;-)

But then if you are sure in advance that one and only one element will match, here's a neat concise solution:

@array=((grep $_ ne $wanted, @array), $wanted);
You can patch it so that it works also if the above conditions are not verified, but won't be just as elegant. (Also left as an exercise to the reader!)

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[atcroft]: james28909: That particular questions was a bit of trick, actually (depending on the country you are in). More interesting is, if you are trying to subtract from an epoch time, for instance, you might have to consider when/if DST occurs for a location,
[atcroft]: because you may have to adjust the number of seconds you change from an epoch from 86400 (not to mention leap seconds)....
[atcroft]: james28909: Although if your program is using a database, you might be able to "pass the buck" to the database and ask it to do the date change for you....
[stevieb]: ++ atcroft

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