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Re^4: Secret Perl Operators: the boolean list squash operator, x!!

by Jenda (Abbot)
on Jul 31, 2006 at 17:44 UTC ( #564819=note: print w/ replies, xml ) Need Help??


in reply to Re^3: Secret Perl Operators: the boolean list squash operator, x!!
in thread Secret Perl Operators: the boolean list squash operator, x!!

I see. Actually to prevent confusion ... even this would autovivify:

@a = ( $hash{foo}{bar} x!! 0);
I guess we'd need to "fix" the x operator to not evaluate the lefthand operator if the righthand one is <=0.

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