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Re^2: if ($2) behaves differently than if (defined $2)

by radiantmatrix (Parson)
on Apr 15, 2008 at 18:09 UTC ( #680611=note: print w/replies, xml ) Need Help??

in reply to Re: if ($2) behaves differently than if (defined $2)
in thread if ($2) behaves differently than if (defined $2)

That's a choice quote. Put another way, the OP is suffering from some confusion that if (defined $x) is intended to be the same as if ($x). In fact, they serve different purposes.

defined tests whether a variable has any value -- a false value is still a value.

Short demonstration code:

my $x; demonstrate(); $x = 1; demonstrate(); $x = 0; demonstrate(); sub demonstrate { if (defined $x) { print "\$x has value $x\n"; } else { print "\$x is undefined\n"; } if ($x) { print "\$x evaluates as TRUE\n"; } else { print "\$x evaluates as FALSE\n"; } print "\n"; }

This produces the following output:

$x is undefined $x evaluates as FALSE $x has value 1 $x evaluates as TRUE $x has value 0 $x evaluates as FALSE
Ramblings and references
The Code that can be seen is not the true Code
I haven't found a problem yet that can't be solved by a well-placed trebuchet

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Re^3: if ($2) behaves differently than if (defined $2)
by repellent (Priest) on Apr 16, 2008 at 16:57 UTC
    Apparently, in Lisp, this is referred to as a semi-predicate problem.

    The very fact that you are using
    if ($2)
    followed by
    $price = $1 . "." . $2
    shows that you are using $2 as a semi-predicate, i.e. to show validity and to hold value.

    Next time, whenever you use if ($var), you should consider if $var needs to be a full-predicate, i.e. strictly a boolean to only show true-or-false.

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