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Re: Efficient way to fork processes and keep a running count?

by targetsmart (Curate)
on Jan 28, 2010 at 05:33 UTC ( #820090=note: print w/replies, xml ) Need Help??


in reply to Efficient way to fork processes and keep a running count?


As per the scenarios you showed, IMHO, there is no need to fork a fourth child, the second child can do the read of disc4 once it is done with disc2.
As only 3 drives exist, 3 processes at a time would be sufficient, that too reusing the existing pool of processes without forking a new one is a good idea.
Forking more number of processes would increase unnecessary complexity.


Vivek
-- 'I' am not the body, 'I' am the 'soul'/'consciousness', which has no beginning or no end, no attachment or no aversion, nothing to attain or lose.
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Re^2: Efficient way to fork processes and keep a running count?
by ikegami (Pope) on Jan 28, 2010 at 06:04 UTC
    You are violently agreeing with the OP. He said the fourth child should be forked after one of the original three had exited, meaning at most three children exist at any given time.

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[james28909]: also remember, that if 'Today' is may 1, then Yesterday is not may 31 lol
[james28909]: theoretically speaking ofcourse
[james28909]: so if you subtracting as you loop, be aware that you will eventually be subtracting into a past month, or year <.<
[james28909]: dontcha love it!
[james28909]: Today would be scalar localtime. Yesterday would be scalar localtime - 1. sunday - monday would variate scalar localtime - ?
[james28909]: oops s/sunday - monday/sunday - saturday/
[james28909]: my mind is blown haha

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