XML::Parser Help!

[Anonymous Monk]

Hi Monks, I am parsing a XML file and instead of getting the value of this variable I am getting the representation of the hash, What I am doing wrong, I can't see it anymore, here is a sample code of where the issue is:

 my $get_phone="";
 
  if (ref($xml_data->{'mainA'}->{'mainB'}->{'mainC'}) eq 'ARRAY') {
      $get_phone = $xml_data->{'mainA'}->{'mainB'}->{'mainC'}->[0];
    } else {
      $get_phone = $xml_data->{'mainA'}->{'mainB'}->{'mainC'};
    }
     
    $got_phone = $get_phone->{'mainD'}->{'mainE'}->{'mainF'}->{'mainG'
+};
    
print "<br>**$got_phone**<br>";

# I am getting this Result: **HASH(0xa8f8064)**

Thanks for the help!

[runrig]

I'm assuming you're using XML::Simple. Look at the ForceArray option so that you done have to check whether a node gets turned into an arrayref or hashref. It might be easier to just use XML::LibXML directly if the document is not too large, or XML::Twig or XML::Rules if it is large.

That being said, what you have left is a hashref, so you need to dereference it further to get your desired results. You can use Data::Dumper to see what further dereferencing needs to be done on the variable. If you had actual runnable sample code, this would be easier to debug.

[rovf]

I'm assuming you're using XML::Simple.

Unlikely, because the subject line refers to XML::Parser. But otherwise, your suggestions - in particular the idea to use Data::Dumper, are of course correct.

[Jenda]

XML::Parser itself would not produce a data structure similar to the one accessed in the code example. Even though it can produce a data structure out of the XML, it would look very different.