in reply to Re: Hash Printing reveals Hash Memory Location
in thread Hash Printing reveals Hash Memory Location
The expression $english && $foreign will evaluate to either true (1) or false ("") but will never be equal to '-1'.
Wrong. The "&&" operator doesn't return 1 or "". It returns the expression on the right side of "&&" if and only if both expressions are true.
my $english = 'foobar';
my $foreign = -1;
say ($english && $foreign); # says "-1"
say ($foreign && $english); # says "foobar"