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Re: s/Perl/SQL/ ?

by Neighbour (Friar)
on Sep 11, 2012 at 08:37 UTC ( #992954=note: print w/replies, xml ) Need Help??

in reply to s/Perl/SQL/ ?

Let's see if I can still do this:
my $ar_data = $dbh->selectall_arrayref(qq ( SELECT noot.Reference, aap.Comparitor, aap.entity_name FROM ( SELECT ? AS Comparitor, entity_name FROM e_annotation_090812.annotation AS A JOIN e_annotation_090812.Temp_table AS T ON A.user = T.Line WHERE IFNULL(A.entity_name, '') <> '' AND A.evidence_code NOT LIKE '%_________8__' AND A.centre = ? ) AS aap JOIN ( SELECT ? AS Reference, entity_name FROM e_annotation_090812.annotation AS B JOIN e_annotation_090812.Temp_table AS U ON B.user = U.Line WHERE IFNULL(B.entity_name, '') <> '' AND B.evidence_code NOT LIKE '%_________8__' AND B.centre = ? ) AS noot ON aap.entity_name = noot.entity_name ), { Slice => {} }, ".${Comparitor}.", ".${Comparitor}.", ".${Referenc +e}.", ".${Reference}.") or die("Error executing query: " . $dbh->errs +tr);
Note that this is untested :)
Feedback is appreciated

Edit: Could you provide a small portion of (dummy) testdata to work with, as well as the DDL (the result of SHOW CREATE TABLE e_annotation_090812.annotation) of both tables?
This is handy to find further optimizations (for example, if evidence_code is a numerical field, using LIKE is very bad as it needs to typecast and thus can't use an index if present).

Edit2: Changed centre LIKE ? to centre = ? which should be better unless you're using wildcards (_ or %) in $Reference or $Comparitor

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