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Coming in at a whopping 223(!) characters, a first attempt:
```for(0..\$#_){if(\$_[\$_]=~/X/){\$t+=10+(\$_[\$_+1]=~/X/?10:\$_[\$_+1])+(\$_[\$_+
+2]=~/X/?10:(\$_[\$_+2]=~/\//?10-\$_[\$_+1]:\$_[\$_+2]))}if(\$_[\$_+1]=~/\//){
+\$t+=10+(\$_[\$_+2]=~/X/?10:\$_[\$_+2]);splice@_,\$_+1,1;last if!defined\$_[
+\$_+2]}else{\$t+=\$_[\$_]}}\$t
There has to be a better way... I thought about switching the if-elsif-else to BLOCK,next if(EXPR);, but I couldn't figure a way to get rid of the splice in the elsif block. *shrugs*

Update: for(0..\$#_){if(\$_[\$_]=~/X/){\$t+=10+(\$_[\$_+1]=~/X/?10:\$_[\$_+1])+(\$_[\$_+2]=~/X/?10:(\$_[\$_+2]=~/\//?10-\$_[\$_+1]:\$_[\$_+2]));last if!defined\$_[\$_+3]}if(\$_[\$_+1]=~/\//){\$t+=10+(\$_[\$_+2]=~/X/?10:\$_[\$_+2]);splice@_,\$_+1,1;last if!defined\$_[\$_+2]}else{\$t+=\$_[\$_]}}\$t

That fixes the perfect score problem. Comes in at 242.

Update2: With some ideas from chipmunk, I'm down to 208. (I didn't want to steal his concept, but improve my own. *grins*)

```@b=@_;sub X{pop=~X?10:pop}while((\$_=shift@b)+1){\$t+=10+X((\$b[0])x2)+X(
+(\$b[1]=~/\//?10-\$b[0]:\$b[1]),\$b[1])and(defined\$b[2]||last)if/X/;if(\$b
+[0]=~m!/!){\$t+=10+X((\$b[1])x2)and(defined\$b[2]||last)}else{\$t+=\$_}}\$t

------
/me wants to be the brightest bulb in the chandelier!

Vote paco for President!

In reply to Re: (Golf) Let's go bowling by dragonchild
in thread (Golf) Let's go bowling by virtualsue

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