It's worth noting that your elsif could easily be replaced by a simple else ;-).
I would probably end up opting for:
$bar && $foo > 6 ? bar_func($foo) : other_bar_func();
$baz && $foo > 6 ? baz_func($foo) : other_baz_func();
$quux && $foo > 6 ? quux_func($foo) : other_quux_func();
Of course if you've got code in the block and not just
subroutine calls that might get a little ugly. But it's
dense (I like dense) and (to me) straight forward.
UPDATE: Yes, I got the condition wrong (that's what I get for thinking in integers ;-).
Quoth a maven, "it's a dispatch table without a hash!"
UPDATE2: Umm it seems the "?" walked off, they are back.
perl -pe "s/\b;([st])/'\1/mg"
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