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I started with the assumption that the partition of 1 was [ [ 1 ] ] and that the partion of each larger one was each sub partion with 1 added to the end, and with one added to each element. Hmm that was more confusing than in my head. Well here, the partition of 2 is [ [ 1 + 1] , [1 , 2]][ [ 1 + 1] , [1 , 1]] and the partition of 3 is [ [ 2 + 1], [1 + 1, 2], [1, 2 + 1], [1 , 2 , 1]]. Well if that hasn't made any sense here is the code.

use strict; use warnings; use Data::Dumper; sub partition { my $num = shift || 1; my $temp = [ [1] ]; # updated 0 to 2 in the following, # since we start with one, the first add_one gets us to two. $temp = add_one($temp) for (2 .. $num); return $temp; } sub add_one { my $combinations = shift; my $temp; foreach my $combination (@$combinations) { foreach my $element (@$combination) { $element++; push @$temp, [ @$combination ]; $element--; } push @$temp, [ @$combination, 1 ]; } my $hash; foreach my $combination (@$temp) { $hash->{ join("-", sort @$combination) }++; } return [ map { [ split "-", $_ ] } keys %$hash ]; } print Dumper(partition(10) );

Oh and I added in some code to stop it from accumulating duplicates.

Updates: Thanks blockhead for noticeing some errors there

Eric Hodges

In reply to Re: Generator of integer partitionts of n by eric256
in thread Generator of integer partitionts of n by chiburashka

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    [1nickt]: my $x = $aohoaoh->[0]->{' foo'}->[0]->{'bar' }; should work
    [thepkd]: not indexing
    [thepkd]: getting data out of the ds
    [choroba]: it depends. Give more details, please
    [thepkd]: i used a series of {}'s but it dont work
    [choroba]: You need square brackets for arrays
    [GotToBTru]: you can certainly construct a single expression to access any part of the data structure, without using temp variables. but you might make it easier on yourself and any other poor soul who has to understand your code if you do
    [thepkd]: to dereference i mean
    LanX .oO( oh tempz, oh moretz)
    [thepkd]: @GotToBTru Sure. But.

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