Re: Wordfeud racks

[RichardK]

How many tiles are in the bag?

for example, if it's only 100 then you're going to have to create 80,678,106,432,000 unique combinations - which might take a while :)

[choroba]

How did you get the number? Combinations

$ echo $(echo {2..100} | sed 's/ /*/g') \
       / $(echo {2..7} | sed 's= =/=g') \
       / $(echo {2..93} | sed 's= =/=g') | bc
16007560800

Also confirmed at http://www.mathsisfun.com/combinatorics/combinations-permutations-calculator.html and http://easycalculation.com/statistics/permutation-combination.php.

[RichardK]

Sorry, I meant permutations, so there a N!/(N-K)! ways to select K tiles from a bag of N.

Or for 7 of 100 tiles = 100*99*98*97*96*95*94 permutations.

I think it will be easier to calculate the probabilities of the different combinations rather than count them, but it's still going to be a fair amount of work.