Re: Does die() change the order of execution?

[jwest]

What you're seeing is an illusion. Since you're looking at STDOUT (the target of print) and STDERR (the target of die) at the same time, it looks like that's the order it's executing in. In all actuality, it's happening in the order you expect, but the buffers are being flushed in the "wrong" order, creating the discrepancy.

Hope this helps!

--jwest

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