Re: Can you explain the result?

[RMGir]

Sure. The result of your function is the value 1, and that's what you're passing to Dumper...

Now, if you called

print Dumper(\&func);

on the function reference, you'd get a slightly more interesting result:

$VAR1 = sub { "DUMMY" };

I guess my version of Dumper isn't up to decompiling subs - I'm guessing that's expected.

[PerlOnTheWay]

shouldn't  1 and 0 be false/0?

[RMGir]

As choroba said, return 1&&0 is different from return 1 and 0.

$ perl -MB::Deparse -e'
   sub f{return 1 and 0;}; 
   sub g{return 1 && 0}; 

   $deparse=B::Deparse->new(); 

   print "f(): ",$deparse->coderef2text(\&f),"\n"; 
   print "g(): ",$deparse->coderef2text(\&g),"\n";' 

f(): {
    0 if return 1;
}
g(): {
    return 0;
}