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in reply to Re^2: How to call a sub-routine ref
in thread How to call a sub-routine ref

For that particular case, you don't need either the -> or the &{}:

sub x{ say "x got [ @_ ]"; };; $h{x} = \&x;; $href = \%h;; $href->{x}('fred','bill');; x got [ fred bill ]

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