in reply to Re^2: How to call a sub-routine ref
in thread How to call a sub-routine ref
For that particular case, you don't need either the -> or the &{}:
sub x{ say "x got [ @_ ]"; };; $h{x} = \&x;; $href = \%h;; $href->{x}('fred','bill');; x got [ fred bill ]
With the rise and rise of 'Social' network sites: 'Computers are making people easier to use everyday'
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