in reply to Re^3: Secret Perl Operators: The Highlander's List Asserter
in thread Secret Perl Operators: the boolean list squash operator, x!!
Hmm? Is that platform dependent?
lt-gm [gm] 21:43 ~ > perl -le 'print "[", !!1, "]"' [1]
Linux, perl 5.8.8. I choose "Higlander Operator" following the unstated naming conventions other secret operators follow ;-)
--shmem
_($_=" "x(1<<5)."?\n".q·/)Oo. G°\ /
/\_¯/(q /
---------------------------- \__(m.====·.(_("always off the crowd"))."·
");sub _{s./.($e="'Itrs `mnsgdq Gdbj O`qkdq")=~y/"-y/#-z/;$e.e && print}
|
|---|
In Section
Meditations