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(tye)Re: meaning of /o in regexes

by tye (Sage)
on Dec 07, 2002 at 06:01 UTC ( #218222=note: print w/replies, xml ) Need Help??

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  1. or download this
        sub foo {
            $y =~ /$x/o;
        }
    
  2. or download this
        BEGIN {
            my $re;
            sub foo {
    ...
                $y =~ $re;
            }
        }
    

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