note sundialsvc4 These two operators exhibit what is called short-circuit evaluation.   If the left-hand side of <tt>&&</tt> is found to be False, the right-hand side is not evaluated at all, since to do so would be pointless:   “False <tt>and</tt> anything-at-all is already known to be False.”   Likewise, if the left-hand side of <tt>||</tt> is found to be True, then the right-hand side is not evaluated since what it’s got is already sufficient:   “True <tt>or</tt> anything-at-all is already known to be True.” The computer had to evaluate <tt>apple</tt> to conclude if it was True or False.   (It was True.)   Since it was True, short-circuiting did not occur so it proceeded to its rightmost part.   But, having evaluated <tt>banana</tt> in the parenthesized expression (also True), that did short-circuit:   within that subexpression, it did not have to go further.   A call to <tt>cherry</tt> will never occur in this program fragment as-written. 1013066 1013066