note
farang
<p>From [doc://perlsub]:<br><br>
<tt> As the last character of a prototype, or just before a
semicolon, a @ or a % , you can use _ in place of $ : if this
argument is not provided, $_ will be used instead.</tt>
</p><p>So I guess _ being the only character in the prototype, is also the last, and is equivalent to $ there.</p>
<p><b>Update:</b> I see from the response of [Athanasius] above that my guess is slightly off. I didn't quite understand what the documentation is saying.</p>
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