As you see, a 0
is printed at the place of the subroutine call. That is of course the return 0
from your subroutine.
But the print in your subroutine happens before the print of the heredoc and hence it shows up --as expected-- before the heredoc. You are not printing into the heredoc, but directly to your standard output device!
A program should be light and agile, its subroutines connected like a string of pearls. The spirit and intent of the program should be retained throughout. There should be neither too little or too much, neither needless loops nor useless variables, neither lack of structure nor overwhelming rigidity." - The Tao of Programming, 4.1 - Geoffrey James
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