Re^5: Efficient way to replace a set of values with another set of values

Ha ha. I spent an inordinate amount of time trying to make a one-liner solution for arbitrarily large numbers (where it would go to "aa" after "z"). However, it turned out that today is Friday and I can't think that hard.

When's the last time you used duct tape on a duct? --Larry Wall

Comment on Re^5: Efficient way to replace a set of values with another set of values

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Re^6: Efficient way to replace a set of values with another set of values by tobyink (Canon) on Nov 23, 2012 at 16:00 UTC
You were looking for: `s/^(\d+)/$n=$1;$l="a";$l++while--$n;$l/meg` [download] Doesn't cope with 0 especially well. `perl -E'sub Monkey::do{say$_,for@_,do{($monkey=[caller(0)]->[3])=~s{::}{ }and$monkey}}"Monkey say"->Monkey::do'`	[reply] [d/l]


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