Re: $1 not "freezing" in an addition

[bart]

in reply to $1 not "freezing" in an addition

Does it work better if you "unreverse" the if condition?

if(s/\(#:(\d+)\)/#/) { 
    return $1 + distance($_);
}

As I don't have the whole code, it's a bit difficult to test. And it's just a hunch.

[grondilu]

Nope. (It was actually initially written as such, anyway)